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Which of the following chromosomal aberrations can result in unmasking recessive alleles resulting in their expression?


A) deletions
B) duplications
C) inversions
D) translocations

E) A) and D)
F) All of the above

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You make meiotic chromosome preparations of two species of tetraploid plants.In one,there is normal pairing of chromosomes and tetrads (quadivalents)are observed,while in the other,there is abnormal pairing in some preparations and trivalents and univalents are seen.How would you account for the differences between these two species?

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The first is an allotetraploid and the c...

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A wild-type chromosome can be represented as ABC[*]DEFGH,and from this a chromosomal aberration arises that can be represented ABC[*]DEGFH,where [*] represents the centromere.This aberration is known as a:


A) deletion.
B) duplication.
C) paracentric inversion.
D) pericentric inversion.
E) translocation.

F) D) and E)
G) A) and B)

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The diagram below shows the chromosomes of a plant that is heterozygous at six loci as well as for a reciprocal translocation involving the chromosomes that carry these loci. The diagram below shows the chromosomes of a plant that is heterozygous at six loci as well as for a reciprocal translocation involving the chromosomes that carry these loci.   This plant is crossed to a plant with normal chromosomes that is homozygous recessive at all loci,and the progeny was comprised of about 250 individuals,half of them phenotypically ABDEFG and half abdefg.This result suggests that: A) multiple crossovers occurred. B) no crossovers occurred. C) segregation was always adjacent. D) segregation was always alternate. E) the six loci are unlinked. This plant is crossed to a plant with normal chromosomes that is homozygous recessive at all loci,and the progeny was comprised of about 250 individuals,half of them phenotypically ABDEFG and half abdefg.This result suggests that:


A) multiple crossovers occurred.
B) no crossovers occurred.
C) segregation was always adjacent.
D) segregation was always alternate.
E) the six loci are unlinked.

F) B) and D)
G) C) and D)

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Assume that x is a new mutant allele in corn.An x/x plant is crossed with a triple-10 individual (trisomic for chromosome 10)carrying only normal dominant alleles at the x locus.Trisomic progeny for chromosome 10 are recovered and crossed back to x/x. a)What ratio of dominant to recessive phenotypes is expected if the x locus is not in chromosome 10? b)What ratio of dominant to recessive phenotypes is expected if the x locus is in chromosome 10?

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a)1:1 ratio of X/x and x/x
b)...

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The red fox has 17 pairs of large,long chromosomes.The arctic fox has 26 pairs of smaller shorter chromosomes.What do you expect to be the chromosome number in somatic tissues of a red fox/arctic fox hybrid?


A) 13
B) 17
C) 26
D) 43

E) B) and C)
F) A) and B)

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A reciprocal translocation happened between chromosomes 1 and 2 in a wild species of strawberries.Below is a diagram of (unreplicated) chromosomes 1 and 2 for the translocated strain of strawberries.N1 and N2 indicate the normal chromosomes 1 and 2,respectively;T1 and T2 are their translocated counterparts. A reciprocal translocation happened between chromosomes 1 and 2 in a wild species of strawberries.Below is a diagram of (unreplicated) chromosomes 1 and 2 for the translocated strain of strawberries.N1 and N2 indicate the normal chromosomes 1 and 2,respectively;T1 and T2 are their translocated counterparts.   Which chromosomes must segregate from one another at anaphase I to form viable meiotic products? A) N1 and N2 separate from T1 and T2. B) N1 separates from N2,T1,and T2. C) N1 and T1 separate from N2 and T2. D) N2 and T1 separate from N1 and T2. E) T1 separates from T2,N1,and N2. Which chromosomes must segregate from one another at anaphase I to form viable meiotic products?


A) N1 and N2 separate from T1 and T2.
B) N1 separates from N2,T1,and T2.
C) N1 and T1 separate from N2 and T2.
D) N2 and T1 separate from N1 and T2.
E) T1 separates from T2,N1,and N2.

F) B) and E)
G) None of the above

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In the flowering plants (the angiosperms) ,the process of double fertilization occurs.This is where one sperm nucleus from the pollen grain fertilizes the egg,and the other fuses with the two polar nuclei in the female gametophyte to produce the triploid (3n) endosperm tissue.The aleurone layer (the outer layer of cells of the endosperm) can be colored or colorless.The allele C causes color (purple) ,and the allele c gives colorless aleurone.A plant is of genotype Cc and self-pollinates.What ratio of colored to colorless aleurone layered endosperms are expected in the progeny?


A) 1:1
B) 2:1
C) 3:1
D) 10:1

E) B) and C)
F) None of the above

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Suppose that in a certain diploid fish genes A and T are on chromosomes 4 and 7,respectively.A female fish is heterozygous at both loci and is also heterozygous for a reciprocal translocation between chromosomes 1 and 4.The translocation breakpoint on chromosome 4 is 10 map units away from the a allele (A is located on the normal chromosome 4) . If this female is crossed to a male of genotype a/a;t/t and with normal chromosomes,what percentage of the progeny is expected to be phenotypically A;T and have only normal chromosomes?


A) 0%
B) 2) 5%
C) 22.5%
D) 25%
E) 45%

F) C) and D)
G) A) and E)

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The fungal cross ad,pan × +,+ (where ad and pan are two linked loci) gave only the following two types of tetrads:  Tetrad I  Tetrad 2  Spore 1  ad,pan ad, pan  Spore 2  aborted ad,+ Spore 3  aborted +, pan  Spore 4 ++++,+\begin{array} { l l l } & \text { Tetrad I } & \text { Tetrad 2 } \\\text { Spore 1 } & \text { ad,pan } & a d , \text { pan } \\\text { Spore 2 } & \text { aborted } & a d ,+ \\\text { Spore 3 } & \text { aborted } & +,\text { pan } \\\text { Spore 4 } & + _ { + } + & + ,+\end{array} These results suggest:


A) a deletion in the wild-type parent.
B) a duplication in one or both parents.
C) an inversion in one of the parents.
D) a translocation in one of the parents,with adjacent segregation.
E) a translocation in one of the parents,with alternate segregation.

F) B) and E)
G) None of the above

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In Drosophila,the phenotype bar-eye is due to a tandem duplication of several bands on the X chromosome.Occasionally (1 out of 1600),all true-breeding stocks of bar-eyed flies yield an even more extreme phenotype called ultrabar,which is in fact due to a triplication of this chromosomal segment.The hypothesis used to explain ultrabar's origin is that a slight mispairing of chromosomes can occur whenever there is a duplication.If crossing-over occurs (in females),then recombinants would form as follows: In Drosophila,the phenotype bar-eye is due to a tandem duplication of several bands on the X chromosome.Occasionally (1 out of 1600),all true-breeding stocks of bar-eyed flies yield an even more extreme phenotype called ultrabar,which is in fact due to a triplication of this chromosomal segment.The hypothesis used to explain ultrabar's origin is that a slight mispairing of chromosomes can occur whenever there is a duplication.If crossing-over occurs (in females),then recombinants would form as follows:    What other evidence,not involving cytological observation,would you seek to substantiate this hypothesis? Be as exact as you can.There are at least two possible answers. What other evidence,not involving cytological observation,would you seek to substantiate this hypothesis? Be as exact as you can.There are at least two possible answers.

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There should be as many wild-type males ...

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In rabbits,genes T and R are located on the same chromosome,20 map units apart.A colleague sends you one of his pure-breeding t r/t r males,which you cross to a T R/T R individual.Each of the T R/ t r F1 heterozygotes is then crossed back to your colleague's double homozygous recessive.Altogether,the backcrosses produce 50 rabbits,of which 24 are T R/t r,24 are t r/t r,1 is T r/t r and 1 is t R/t r. Which of the following explanations best justifies the results?


A) The colleague's rabbit is heterozygous for an inversion that spans at least 16 map units of the region between genes t and r.
B) The colleague's rabbit is heterozygous for an inversion that spans at least 18 map units of the region between genes t and r.
C) The colleague's rabbit is homozygous for an inversion that spans at least 16 map units of the region between genes t and r.
D) The colleague's rabbit is homozygous for an inversion that spans at least 18 map units of the region between genes t and r.
E) The colleague's rabbit carries an inversion that spans the whole region between genes t and r.

F) A) and B)
G) C) and D)

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In the following pedigree,the shaded symbols represent a rare X-linked disease of the blood.The propositus has 45 chromosomes and is sterile.Propose a single mechanism to account for both the sterility and the blood disease in this female. In the following pedigree,the shaded symbols represent a rare X-linked disease of the blood.The propositus has 45 chromosomes and is sterile.Propose a single mechanism to account for both the sterility and the blood disease in this female.   A) The woman's father was a carrier for the disease on his X chromosome. B) The woman is likely demonstrating a case of Turner syndrome. C) The woman is likely demonstrating a case of Down syndrome. D) The woman's mother's eggs likely experienced a nondisjunction event.


A) The woman's father was a carrier for the disease on his X chromosome.
B) The woman is likely demonstrating a case of Turner syndrome.
C) The woman is likely demonstrating a case of Down syndrome.
D) The woman's mother's eggs likely experienced a nondisjunction event.

E) A) and C)
F) C) and D)

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Assume you are studying an organism in which duplications or deficiencies in the gametes are not viable.An individual is heterozygous for a pericentric inversion.A four-chromatids double crossover,with one of the two crossovers within the inversion and the other outside of it,would lead to:


A) four viable gametes,two of them parental and two recombinant.
B) four viable gametes,two of them with the inversion and two without.
C) two viable gametes,both recombinant.
D) two viable gametes,both parental.
E) zero viable gametes.

F) C) and D)
G) D) and E)

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In a tetraploid species,an individual with genotype B/b/b/b was crossed with an individual with genotype b/b/b/b.What is the expected genotypic ratio in the offspring?


A) 1:1
B) 1:2
C) 1:4
D) 1:8
E) 1:16

F) A) and D)
G) A) and E)

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Two strains of Australian wombat were crossed.Meiotic metaphase configurations of the F1 hybrids are diagrammed below. Two strains of Australian wombat were crossed.Meiotic metaphase configurations of the F<sub>1</sub> hybrids are diagrammed below.   In both strains of wombats,n = 4.The black dots are the centromeres,a and b are genetic markers located on chromosome 2,c is located on chromosome 3,and d is located on chromosome 4. a)How do the chromosomes of the two parental strains differ? Use terminology that most accurately describes each chromosomal rearrangement.  Chromosome 1: Chromosome 2: Chromosome 3: Chromosome 4: b)In the two parental strains,the map distance between the a and b loci is not the same.Explain why. c)Assume that during meiosis in the F<sub>1</sub> above,a crossover always occurs between the a locus and the centromere of chromosome 2. (i)What proportion of gametes produced by the F<sub>1</sub> hybrid will be viable? (Note: You must consider the behavior of all 4 chromosomes in answering this question.) (ii)What will be the genotypes of the viable gametes at the a and b loci? (iii)What will be the genotypes of the viable gametes at the c and d loci? In both strains of wombats,n = 4.The black dots are the centromeres,a and b are genetic markers located on chromosome 2,c is located on chromosome 3,and d is located on chromosome 4. a)How do the chromosomes of the two parental strains differ? Use terminology that most accurately describes each chromosomal rearrangement. Chromosome 1: Chromosome 2: Chromosome 3: Chromosome 4: b)In the two parental strains,the map distance between the a and b loci is not the same.Explain why. c)Assume that during meiosis in the F1 above,a crossover always occurs between the a locus and the centromere of chromosome 2. (i)What proportion of gametes produced by the F1 hybrid will be viable? (Note: You must consider the behavior of all 4 chromosomes in answering this question.) (ii)What will be the genotypes of the viable gametes at the a and b loci? (iii)What will be the genotypes of the viable gametes at the c and d loci?

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a)Chromosome 1 appears to be similar in ...

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A hybrid allotetraploid species (2n = 60) was backcrossed to one of the suspected parents (2n = 30) .When the F1 underwent meiosis,the prophase chromosome configuration was examined.If the guess about the suspected parent was correct,what would the chromosome configuration look like?


A) 30 pairs
B) 45 singles
C) 60 singles
D) 15 pairs and 15 singles
E) 30 pairs and 15 singles

F) A) and B)
G) A) and C)

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A particular hybrid species is defined as 3n = 12.It is discovered that at meiosis,pairing is always univalent + bivalent (never trivalent) in this species.How many bivalents will be present in prophase of meiosis I?


A) 2
B) 3
C) 4
D) 8
E) 12

F) D) and E)
G) C) and D)

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A man is found to be karyotypically 47,XYY.The presence of an extra Y chromosome most likely results from:


A) nondisjunction in a maternal meiocyte at meiosis I.
B) nondisjunction in a maternal meiocyte at meiosis II.
C) nondisjunction in a paternal meiocyte at meiosis I.
D) nondisjunction in a paternal meiocyte at meiosis II.
E) unequal crossing over.

F) B) and E)
G) A) and B)

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An allotetraploid plant with 2n = 30 is backcrossed to one of its progenitor species that has an n = 8.A sterile progeny is produced.How many chromosomes will this sterile individual possess,and what are the chromosome numbers of the two progenitor species?

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The allotetraploid can be repr...

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